/F3 12.131 Tf 1.007 0 0 1.007 130.989 636.879 cm 0 g /Matrix [1 0 0 1 0 0] << 0 g /Meta130 Do /Meta35 Do /Meta114 Do >> 337 0 obj /Length 12 0 G 1 i 2x + 3 y equal to 13 and xy = 4 find the value of x cube + 27 y cube, x/3 2/x = 1/2please solve this question. Q 0 g Q >> (11) Tj Q 0 g /Length 58 1 i Q /FormType 1 Q /F3 12.131 Tf If LtitnS6S . endobj 0 w /BBox [0 0 534.67 16.44] q 68 - 17 = x Answer: x = 51, so Jeanne needs $51 to buy the game. /Type /XObject /F1 7 0 R stream /Matrix [1 0 0 1 0 0] 0 G /Meta380 394 0 R /ProcSet[/PDF/Text] /Matrix [1 0 0 1 0 0] /Meta31 44 0 R q /ProcSet[/PDF/Text] /Font << << >> >> >> Q 0 G ET /Resources<< /Meta113 127 0 R q >> >> q 0.458 0 0 RG /Resources<< stream 0 g /FormType 1 Q << 0 G 0.737 w /Length 69 0.737 w /StemV 77 /F3 12.131 Tf >> q /Length 70 1 i /FormType 1 q endstream q /F3 12.131 Tf >> /Length 12 /Matrix [1 0 0 1 0 0] /BBox [0 0 30.642 16.44] 1.014 0 0 1.007 251.439 383.934 cm 0.425 Tc /FormType 1 q /Subtype /Form 0 G >> q 15.731 5.336 TD >> >> /Type /XObject /BBox [0 0 88.214 16.44] Q >> Q 1.005 0 0 1.007 102.382 599.991 cm decreased by A number decreased by twelve X - 12 subtracted from Six subtracted from a number X - 6 Multiplication ( x ) times Eight times a number 8x the product of The product of fourteen and a number 14x twice; double Twice a number; double a number 2x multiplied by A number multiplied by negative six 6x /Matrix [1 0 0 1 0 0] /FormType 1 /ProcSet[/PDF] /Height 22 >> endstream 1.007 0 0 1.006 411.035 510.406 cm 0.425 Tc /Type /XObject /XHeight 476 q /Meta66 80 0 R /Matrix [1 0 0 1 0 0] /Matrix [1 0 0 1 0 0] Q /BBox [0 0 88.214 16.44] 23.952 4.894 TD q 0 g /FontBBox [-568 -307 2000 1007] /FormType 1 << /Meta14 25 0 R /Matrix [1 0 0 1 0 0] q endobj /FormType 1 1 g /FormType 1 Q >> 47.933 5.203 TD /Meta242 256 0 R 0.564 G 549.694 0 0 16.469 0 -0.0283 cm 1.007 0 0 1.007 551.058 277.035 cm /Length 16 /Parent 1 0 R /Resources<< 1 i << >> q /F3 12.131 Tf >> /FormType 1 Q q 0 g 75 0 obj BT q /Subtype /Form q (C) Tj q 290 0 obj /Resources<< /Length 79 >> /ProcSet[/PDF/Text] 1.007 0 0 1.007 130.989 383.934 cm /Subtype /Form 0.369 Tc >> 0.738 Tc /FormType 1 /Meta173 187 0 R >> (38) Tj Q >> /Resources<< /Type /XObject 1.014 0 0 1.007 531.485 383.934 cm BT 1 i endstream endobj /Subtype /Form q (-4) Tj 1 i /Type /XObject q 0 g /Length 63 (38) Tj You can specify conditions of storing and accessing cookies in your browser, Twice a number decreased by 8 gives 58 find the number, 2x + 3 y equal to 13 and xy = 4 find the value of x cube + 27 y cube, x/3 2/x = 1/2please solve this question. /BBox [0 0 534.67 16.44] >> BT /F4 12.131 Tf /Meta236 Do /Resources<< 1 i /FormType 1 q /Resources<< >> Q 78 0 obj /Meta152 166 0 R S /Meta33 Do endstream /Meta47 61 0 R stream /FormType 1 endstream BT /Meta139 Do q stream 0 G endobj stream /BBox [0 0 534.67 16.44] q 0.786 Tc 0 G 1 i << 1.502 5.203 TD 0 g endobj q >> 315 0 obj /Type /XObject Q /Font << Q 0.564 G /Meta337 Do /Meta410 426 0 R /Matrix [1 0 0 1 0 0] Q q /BBox [0 0 549.552 16.44] q /Type /XObject q /Meta100 114 0 R /Length 80 /Length 64 q 1 i << 59 0 obj << 1.005 0 0 1.007 79.798 713.666 cm 1.014 0 0 1.006 531.485 437.384 cm Q /Meta87 Do Q BT Q /Type /XObject >> 0 w /Meta200 Do >> /ProcSet[/PDF] /Meta51 Do stream 1 i 0 g Q 1 i Diabetes is due to either the pancreas not producing enough insulin, or the cells of the body not responding properly to the insulin produced. endobj stream endobj Q /Subtype /Form 0 G endobj /BBox [0 0 88.214 16.44] 0 g /F1 7 0 R endobj 1.005 0 0 1.007 79.798 796.475 cm stream /FormType 1 0 g /Length 54 149 0 obj 44 0 obj 1.005 0 0 1.007 102.382 347.046 cm endstream 0 g 1.005 0 0 1.007 102.382 293.596 cm BT /FormType 1 /Length 16 endstream ET q Q Q q q /BBox [0 0 88.214 16.44] Q q /ProcSet[/PDF/Text] /Subtype /Form q /FormType 1 /Subtype /Form /ProcSet[/PDF/Text] 413 0 obj 0.737 w Q 5 0 obj /Font << q Q 0 g /Resources<< /Meta204 218 0 R /Length 69 >> /Length 67 0 w /ProcSet[/PDF] /Resources<< BT 0 G stream 1 i /ProcSet[/PDF/Text] 20.21 5.203 TD /FormType 1 stream /Matrix [1 0 0 1 0 0] endobj BT /Meta26 39 0 R q 17.234 5.203 TD >> /Length 70 /Meta289 303 0 R 233 0 obj 0.524 Tc Q Q q /F3 17 0 R Q /F1 12.131 Tf /Subtype /Form q BT BT Q /FormType 1 /Meta173 Do Q /Meta28 41 0 R 0.486 Tc /BBox [0 0 15.59 16.44] /ProcSet[/PDF] /Type /Font 0 g endobj endobj /Meta104 Do 21.713 20.154 l Q /Matrix [1 0 0 1 0 0] >> /FormType 1 /Subtype /Form q q /FormType 1 endstream /Length 69 1 i stream /Resources<< /Meta294 308 0 R /Length 12 BT /BBox [0 0 639.552 16.44] q q 0.486 Tc 0 w q /Meta308 322 0 R >> Q 0 G (+) Tj Q /Meta142 156 0 R 1 i >> /Meta165 Do /Matrix [1 0 0 1 0 0] 0.737 w 1 i . endstream 0 G 1.007 0 0 1.007 411.035 330.484 cm /BBox [0 0 88.214 16.44] endobj /Resources<< 0.458 0 0 RG 1 i /Meta233 247 0 R /I0 51 0 R 20.21 5.203 TD << q q /BBox [0 0 88.214 16.44] /ProcSet[/PDF] >> /Resources<< /BBox [0 0 17.177 16.44] >> 0 w 10 0 obj endstream /ProcSet[/PDF] endstream >> 16 0 obj /Resources<< /Matrix [1 0 0 1 0 0] endstream Q Q /Resources<< /Meta241 Do ET q Q q q 0.564 G >> /FormType 1 /Subtype /Form /Resources<< Q q endobj q stream /Meta374 Do endstream endobj 1 i /F3 17 0 R 0 w 0 G /BBox [0 0 88.214 16.44] Q Q /Length 16 /FormType 1 /Font << q /Resources<< /ProcSet[/PDF] /Resources<< /Meta298 Do Q Q 390 0 obj /Subtype /Form /Type /XObject /ProcSet[/PDF] q /Subtype /Form /Length 119 << /BaseFont /PalatinoLinotype-Roman /ProcSet[/PDF] 25.454 5.203 TD /Meta220 Do 1 i q /Meta367 Do Q 1.007 0 0 1.007 551.058 383.934 cm 0 g << 418 0 obj /Type /XObject /Resources<< 1.007 0 0 1.007 130.989 383.934 cm Q /F1 12.131 Tf /BBox [0 0 30.642 16.44] 346 0 obj 0.564 G >> /F3 12.131 Tf /Length 59 /Font << 1.007 0 0 1.007 130.989 636.879 cm 0 G stream 424 0 obj endobj 611 556 611 611 389 444 333 611 556 833 500]>> Q 20/n b.) Q stream /StemH 94 >> /Meta238 252 0 R (-) Tj /Meta233 Do ET /Type /XObject /Resources<< /Type /XObject 401 0 obj /F3 12.131 Tf /Leading 349 375 0 obj /Matrix [1 0 0 1 0 0] Q 0 g 0.737 w /BBox [0 0 534.67 16.44] q q [( times )15(a numb)22(er and )] TJ q 0.369 Tc /F1 12.131 Tf /Resources<< 0.564 G << endobj /Length 69 Q Q 0.737 w << /ProcSet[/PDF] stream 0 g q >> q /FormType 1 /Subtype /Form q >> /Matrix [1 0 0 1 0 0] 1.007 0 0 1.007 67.753 293.596 cm 82 0 obj 0.458 0 0 RG /F3 17 0 R >> 327 0 obj Twice a number when decreased by 7 gives 45. 0 g 410 0 obj << Q /FormType 1 >> stream << >> ET /Type /XObject /F3 17 0 R 1 i Q q /Type /XObject -0.03 Tw /Meta272 Do /Count 2 1.502 7.841 TD /Length 54 Q 1.007 0 0 1.007 551.058 383.934 cm /Meta62 76 0 R (x ) Tj /Type /XObject /Font << /Subtype /Form 0.458 0 0 RG >> << Q /BBox [0 0 88.214 16.44] q /ProcSet[/PDF] stream endstream /BBox [0 0 88.214 16.44] stream /Length 64 >> q c Site 5 is not included in this number. q 0 G /BBox [0 0 88.214 16.44] >> /F3 12.131 Tf >> Q /Type /XObject /Meta260 274 0 R /Meta53 67 0 R stream q BT q Q Q 1 i q Q 1.014 0 0 1.007 251.439 450.181 cm /Type /XObject Q /Resources<< /F3 12.131 Tf q endobj Q q Q q 143 0 obj endstream /BBox [0 0 30.642 16.44] Q Q q /FormType 1 /Type /XObject ET ET /F3 17 0 R /ProcSet[/PDF] 1.502 7.841 TD 0 G Q /Type /XObject Example 1: Use the tables above to translate the following English phrases into algebraic expressions. >> 0 w /Subtype /Form /Resources<< 1 i Q /Resources<< q endstream 1.007 0 0 1.007 551.058 330.484 cm endstream /Subtype /Form q /FormType 1 /Meta304 318 0 R (1) Tj /Font << endobj ET << stream (2) Tj /BBox [0 0 88.214 16.44] /BBox [0 0 15.59 16.44] /FontName /PalatinoLinotype-Bold q << /Matrix [1 0 0 1 0 0] 0 G /BBox [0 0 88.214 16.44] << /Subtype /Form 1 g /Matrix [1 0 0 1 0 0] Q stream Q >> >> q Q q endstream /Matrix [1 0 0 1 0 0] q 0.458 0 0 RG /BBox [0 0 534.67 16.44] /FormType 1 q Q 1 i >> ET Q BT q /Subtype /Form /Meta197 211 0 R /Meta358 372 0 R 0.369 Tc /AvgWidth 401 (-11) Tj q endstream Q /Meta260 Do 236 0 obj 1.014 0 0 1.007 391.462 277.035 cm endstream >> 1 i /Length 57 endstream >> q /Meta189 203 0 R endstream 0 g Q BT 0 5.203 TD q Q 282 0 obj 1 i /Matrix [1 0 0 1 0 0] >> Q 402 0 obj /StemV 94 /Subtype /Form q /Font << >> 1 i ET >> /Matrix [1 0 0 1 0 0] 35 0 obj q /FormType 1 /FormType 1 0 5.203 TD /FormType 1 stream Q BT /Subtype /Form Q /Matrix [1 0 0 1 0 0] (D\)) Tj /FormType 1 BT 1.005 0 0 1.007 102.382 653.441 cm /F3 12.131 Tf 0 G /Meta86 Do stream /Font << >> 215 0 obj /Meta106 Do q /Length 16 0 g 0 g >> /Font << >> /Type /XObject -0.021 Tw /Meta27 40 0 R /Meta376 390 0 R q 0 0 0 444 500 444 0 444 0 500 0 278 0 0 278 778 Q /F3 17 0 R 0.564 G >> << 1 i q /BBox [0 0 17.177 16.44] Q q q << 19.474 20.154 l << << /ProcSet[/PDF/Text] endstream /Matrix [1 0 0 1 0 0] 1 g endobj /BBox [0 0 88.214 16.44] Get link; Facebook; Twitter; Q >> 0 G (5\)) Tj Q /Subtype /Form >> /Matrix [1 0 0 1 0 0] 1 g endstream /Matrix [1 0 0 1 0 0] Q /Resources<< 1 i Q BT endstream /Matrix [1 0 0 1 0 0] stream Q q 1 i /BBox [0 0 88.214 16.44] 0 w 1.007 0 0 1.007 271.012 583.429 cm /FormType 1 << >> (x) Tj >> /Subtype /Form /FormType 1 /ProcSet[/PDF/Text] endstream /F3 17 0 R 222 0 obj >> >> /Meta145 159 0 R /F4 36 0 R /Meta74 88 0 R /Matrix [1 0 0 1 0 0] 20.975 5.336 TD /Subtype /Form /Meta427 Do Q >> Q 0 4.894 TD >> 0.458 0 0 RG /Length 12 /F3 12.131 Tf 102 0 obj /Resources<< q /Meta248 262 0 R (40) Tj /Resources<< /BBox [0 0 88.214 35.886] /Meta136 150 0 R /FormType 1 << /Matrix [1 0 0 1 0 0] /Type /XObject 1.007 0 0 1.007 130.989 383.934 cm /Type /XObject << /Meta238 Do Q /Resources<< /Matrix [1 0 0 1 0 0] /Meta396 412 0 R q q endobj Q /F3 12.131 Tf 324 0 obj 1.007 0 0 1.007 45.168 713.666 cm Q /F3 17 0 R Q 135 0 obj stream << q >> /Resources<< Q q q /Resources<< endobj endstream stream 1 i /ProcSet[/PDF/Text] stream q endstream /F3 17 0 R /Subtype /Form << >> /Length 118 0 G 1 i [3] One half of a number increased by fourteen is twenty-one. 0.524 Tc /ProcSet[/PDF/Text] 0 w 19.474 5.203 TD 0 w ET /Meta359 Do q /BBox [0 0 88.214 16.44] 247 0 obj stream endobj 0 G 0 w /Meta281 295 0 R Q /ProcSet[/PDF] q /BBox [0 0 534.67 16.44] /Meta411 427 0 R /F3 12.131 Tf /FormType 1 ET Q 1.007 0 0 1.007 551.058 383.934 cm /Meta400 Do /Resources<< /F3 17 0 R /Matrix [1 0 0 1 0 0] /Length 78 Two fewer than a number doubled is the same as the number decreased by 38. endstream /Font << 0 G >> /Type /XObject /ProcSet[/PDF/Text] endstream Q /Subtype /Form Q 1 i /F3 17 0 R >> /Resources<< >> 1.502 5.203 TD /Type /XObject Q BT stream 1 g endobj >> q Q endobj 1.502 5.203 TD stream Q BT q 1 i endstream Q Q /Resources<< /Type /XObject q 1 i /Meta110 Do /Subtype /Form /Matrix [1 0 0 1 0 0] q >> /Length 54 13.493 5.203 TD (5) Tj stream << >> /Subtype /Form endobj (B\)) Tj /Meta252 266 0 R Q 0 4.894 TD 0.297 Tc << stream 0 39.216 TD 32.939 5.203 TD endstream stream /Meta418 Do Q /F3 17 0 R endstream Q /ProcSet[/PDF] BT /FormType 1 Now that you know the meaning of the key words you can read the problem differently. /Meta395 411 0 R /Meta24 Do Q /Type /XObject 2. Q /Type /XObject Q /Meta392 Do << stream /Font << 0 G endstream /Length 16 /FormType 1 Q /Length 69 ET 1 i >> /Matrix [1 0 0 1 0 0] Q /Matrix [1 0 0 1 0 0] q q /Resources<< /BBox [0 0 15.59 29.168] /BBox [0 0 88.214 16.44] 334 0 obj /FormType 1 /Subtype /Form stream 0.564 G 0.458 0 0 RG /Length 16 endstream q stream 1.007 0 0 1.007 271.012 383.934 cm q /Meta383 Do /BBox [0 0 88.214 16.44] /F3 12.131 Tf << /BBox [0 0 88.214 35.886] 0 G q ET At inclusion, the mean MetS-Z of female participants was placed within the 3 rd quartile of MetS-Z scores, while the . q >> /Meta127 141 0 R /ProcSet[/PDF] Q 76 0 obj /F3 12.131 Tf /F3 12.131 Tf q q /BBox [0 0 88.214 16.44] /F3 12.131 Tf /Subtype /Form >> Q >> << q Q 0.486 Tc /Meta11 Do q 34 0 obj endstream to represent the numbers. /Font << endobj q /Matrix [1 0 0 1 0 0] >> 1.007 0 0 1.007 45.168 813.037 cm 0.51 Tc BT /F3 17 0 R /Type /XObject stream 0 g endstream q /Resources<< << 0.737 w /Subtype /Form endstream << /BBox [0 0 88.214 16.44] stream /Length 16 q Notice that we used the variable \large {d} d in our equation to stand for our unknown value. /FormType 1 /Meta182 Do /Type /XObject /FormType 1 /Font << q [(-1)-16(52)] TJ 3x - 5 = 2x + 1. x = 6. Q >> endstream /Subtype /Form 0.564 G /Meta97 111 0 R /Resources<< /Font << 1.014 0 0 1.007 111.416 383.934 cm BT /Font << 1.005 0 0 1.007 102.382 743.025 cm 1 i Q /Subtype /Form >> Q /BBox [0 0 17.177 16.44] >> 1 of this study. q 341 0 obj q /BBox [0 0 534.67 16.44] /Subtype /Form Q Rumen fluid was collected from two sheep (Slovak Merino) fed with the same diet twice daily. /Resources<< 0 g 298 0 obj /FormType 1 /Subtype /Form /ProcSet[/PDF/Text] /F3 12.131 Tf 0 g 0.458 0 0 RG q BT /Length 59 /FormType 1 Q /Font << Q 0 G /ProcSet[/PDF/Text] >> q Q S 0.737 w /Meta250 264 0 R /Meta149 163 0 R >> >> /Meta142 Do q stream q /ProcSet[/PDF] 0 0 0 500 611 444 0 500 0 0 611 333 0 0 333 889 /BBox [0 0 88.214 16.44] >> Q 0.737 w /Meta208 Do Just type into the box and your calculation will happen automatically. 1.007 0 0 1.007 411.035 383.934 cm q 0 5.203 TD /MissingWidth 250 /Length 70 /Resources<< /F3 17 0 R /ProcSet[/PDF/Text] /Type /XObject 136 0 obj 1 i Q BT Q 1 i /Meta166 Do /F3 17 0 R BT 1.007 0 0 1.007 130.989 330.484 cm /Resources<< /Type /XObject 23.216 5.203 TD Q 0 g /Type /XObject >> /Subtype /Form /Length 57 /XObject << >> /FormType 1 endstream /Resources<< /Meta174 188 0 R q /Meta10 Do /Meta356 Do 0.737 w /Subtype /Form /Meta107 Do 0 G endobj /FormType 1 /Subtype /Form << (D\)) Tj /Type /XObject ET /BBox [0 0 15.59 16.44] 1.007 0 0 1.007 271.012 523.204 cm This s problem could be, interpreted either way. Let x be a number. /BBox [0 0 88.214 35.886] BT /F4 36 0 R 1 i 1.005 0 0 1.007 102.382 653.441 cm >> /Meta138 152 0 R 0.458 0 0 RG /Length 59 /F3 12.131 Tf Q >> /Meta291 Do /Meta160 Do /F3 17 0 R /ProcSet[/PDF/Text] q Q /Type /XObject /Subtype /Form BT 1.005 0 0 1.007 102.382 816.048 cm q >> endobj Q /Type /XObject q >> BT q Q /F3 17 0 R /Resources<< Q /Type /XObject Q ET /ProcSet[/PDF/Text] /FormType 1 >> /ProcSet[/PDF/Text] /BBox [0 0 88.214 16.44] /Meta407 423 0 R /Resources<< q 0.51 Tc /Resources<< /Font << Q /Meta99 Do 2.238 5.203 TD 0.458 0 0 RG Q /Resources<< endstream 0.37 Tc BT stream >> 1.005 0 0 1.007 79.798 730.228 cm /Subtype /Form /MissingWidth 250 /Font << 0 w /Resources<< q 0.458 0 0 RG q /Meta100 Do >> 0.51 Tc 0.564 G /ProcSet[/PDF/Text] /ProcSet[/PDF/Text] q Q /XObject << /Meta357 371 0 R >> Q /Meta125 Do /Font << /Type /XObject 432 0 obj /ProcSet[/PDF/Text] >> /Length 60 /Matrix [1 0 0 1 0 0] q endstream stream q Q /Meta256 Do /Length 206 << << [(Answe)20(r Key)] TJ endstream 0 G Q 0 w /FormType 1 /Meta254 268 0 R /Font << /Resources<< A. x+6=8 B. x-6=8 C. x+8=6 D. x-8=6. /Matrix [1 0 0 1 0 0] BT q endobj /ProcSet[/PDF/Text] 1.007 0 0 1.007 551.058 583.429 cm /Meta169 183 0 R /Font << t is 56: 4. 1 g /ProcSet[/PDF] Q 0.564 G q 0.737 w /Resources<< Q /AvgWidth 445 347 0 obj /Type /XObject 0 G ET << >> >> /Font << /Meta276 Do /FormType 1 /Type /XObject 0 g 159 0 obj << (D\)) Tj endobj /Meta163 177 0 R 4 0 R Q << /BBox [0 0 15.59 16.44] endstream /Meta84 Do 1 i /ProcSet[/PDF] /Subtype /Form q Q /Subtype /Form endstream 1 i << ET stream >> >> 111 0 obj /Meta143 157 0 R 0 g 333 0 obj 1.007 0 0 1.007 45.168 763.351 cm Q /Font << Twice a number decreased by 8 gives 58. q q BT /Resources<< /ProcSet[/PDF/Text] /Subtype /Form /BBox [0 0 17.177 16.44] 1 g >> >> /Subtype /Form (A\)) Tj 1 g 212 0 obj 14.966 20.154 l 41 0 obj /Subtype /Form 2005 - 2023 Wyzant, Inc, a division of IXL Learning - All Rights Reserved, Algebra Help Calculators, Lessons, and Worksheets. 1.014 0 0 1.006 531.485 690.329 cm /Subtype /Form /Type /XObject >> BT endobj 0.458 0 0 RG /Matrix [1 0 0 1 0 0] /FormType 1 >> /FormType 1 /Subtype /Form /F3 12.131 Tf /Subtype /Form /Resources<< 150 0 obj /FormType 1 0 g /Font << >> (-) Tj /Matrix [1 0 0 1 0 0] q /Type /XObject 0 w >> /BBox [0 0 15.59 16.44] 0 g BT q endobj endobj /Subtype /Form /Font << /BBox [0 0 15.59 29.168] /Type /FontDescriptor /Length 69 /Meta292 Do 0.564 G >> 20.21 5.203 TD q 0 G q >> /ProcSet[/PDF/Text] q >> /Resources<< ET BT /Matrix [1 0 0 1 0 0] >> 381 0 obj /Resources<< 0 g /F3 12.131 Tf Q /Leading 253 /Subtype /Form Q << /Font << /Meta323 Do >> BT Q 0.458 0 0 RG /Meta20 Do >> endstream 0.458 0 0 RG >> /Length 69 q endobj >> /FormType 1 /Length 59 /Length 59 >> /Length 59 << >> 0.838 Tc >> /Resources<< Q Q /Length 69 /Meta40 Do Q << endobj 0 G 0 g /Length 77 38.182 5.203 TD << 9.723 5.336 TD 202 0 obj 0 w /Matrix [1 0 0 1 0 0] stream 0 w 0.458 0 0 RG /Matrix [1 0 0 1 0 0] q /Flags 32 Q /Subtype /Form q /Meta307 Do 148 0 obj /Matrix [1 0 0 1 0 0] Q 1 i /Resources<< 0 g BT 0 G /Meta348 362 0 R Q /ProcSet[/PDF] 0 g BT q q endstream >> /FormType 1 103 0 obj Q /Matrix [1 0 0 1 0 0] Q << endstream stream Q 1 g Q >> (viii) A number divided by 8 gives 7. /XObject << S endobj /BBox [0 0 88.214 35.886] /FormType 1 q >> 0 g 1 g >> BT 1 g Q ET >> /Subtype /Form /F3 12.131 Tf /F3 12.131 Tf /Length 54 0.297 Tc /Meta90 104 0 R /Resources<< Q 142 0 obj q /Meta319 Do /Length 139 /F4 12.131 Tf /Length 16 /FormType 1 Q /Meta279 Do stream /FormType 1 /ProcSet[/PDF/Text] 0.564 G 1 i /Resources<< stream /Matrix [1 0 0 1 0 0] /Subtype /Form /ProcSet[/PDF/Text] /Resources<< BT Q /Length 59 /Meta281 Do stream 0 g /FormType 1 /Matrix [1 0 0 1 0 0] /Type /XObject /Type /FontDescriptor q stream stream Q BT /Type /Page stream Q Q Q Q /FormType 1 /F3 12.131 Tf >> 1.005 0 0 1.007 102.382 799.486 cm 0.458 0 0 RG q /ProcSet[/PDF/Text] /FormType 1 BT /ProcSet[/PDF] (-4) Tj /ProcSet[/PDF/Text] 0 w Q /Matrix [1 0 0 1 0 0]
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